The Total solution for NCERT class 6-12
Answer - 1 : - Chlorination of methane is a free radical reaction which occurs by the following mechanism:
Fromthe above mechanism, it is evident that during propagation step, CH3 free radicals areproduced which may undergo three reactions, i.e., (i) — (iii). In the chaintermination step, the two CH3 freeradicals combine together to form ethane (CH3—CH3)molecule.
Answer - 2 : -
Answer - 3 : - (a) Isomers of C4H8 having one double bond are:
Answer - 4 : -
Answer - 5 : -
Step 1. Write the structure of the products side by side withtheir oxygen atoms pointing towards each other.Step 2. Remove the oxygenatoms and join the two ends by a double bond, the structure of the alkene ‘A’is
Answer - 6 : -
(i) An aldehyde with molar mass of44 u is ethanal, CH3CH=0(ii) Write two moles of ethanal side by side with their oxygen atoms pointingtowards each other.(iii) Remove the oxygen atoms and join them by a double bond, the structure ofalkene ‘A’ isAs required, but-2-ene has three C—C, eight C—H a-bonds and one C—C π-bond.
Answer - 7 : - (i)Write the structures of propanal and pentan-3-ene with their oxygen atomsfacing each other, we have,(ii) Remove oxygen atoms and join the two fragments by a double bond, thestructure of the alkene is
Answer - 8 : -
Answer - 9 : -
The structures of cis- andtrans-isomer of hex-2-ene are:The boiling point of a molecule depends upon dipole-dipole interactions. Sincecis-isomer has higher dipole moment, therefore, it has higher boiling point.
Answer - 10 : -
The six electrons of the p-orbitalscover all the six carbon atoms, and are said to be delocalized. As a result ofdelocalization there formed a stronger n-bond and a more stable molecule.