The Total solution for NCERT class 6-12
Answer - 1 : -
Perimeter of figure (a) = 4 × side = 4 × 60 = 240 mPerimeter of figure (b) = 2 [l + b]Perimeter of figure (b) = Perimeter of figure (a)2[l + b] = 240⇒ 2 [80+ b] = 240⇒ 80 + b= 120⇒ b =120 – 80 = 40 mArea of figure (a) = (side)2 =60 × 60 = 3600 m2Area of figure (b) = l × b = 80 × 40 = 3200 m2So, area of figure (a) is longer than the area of figure (b).
Answer - 2 : -
Area of the plot = side × side = 25 m × 25 m = 625 m2Area of the house = l × b = 20 m × 15 m = 300 m2Area of the garden to be developed = Area of the plot – Area of the house = 625m2 –300 m2 =325 m2Cost of developing the garden = ₹ 325 × 55 = ₹ 17875
The shape of a garden isrectangular in the middle and semicircular at the ends as shown in the diagram.Find the area and the perimeter of this garden. [Length of rectangle is 20 –(3.5 + 3.5) metres]
Answer - 3 : -
Given: Total length = 20 m
Diameter of semi circle = 7 m
Radius of semi circle = 7/2 = 3.5 m
Length of rectangular field
= 20-(3.5+3.5) = 20-7 = 13 m
Breadth of the rectangular field = 7 m
Area of rectangular field = l×b
= 13×7= 91m2
Area of two semi circles = 2×(1/2)×π×r2
= 2×(1/2)×22/7×3.5×3.5
= 38.5 m2
Area of garden = 91+38.5 = 129.5 m2
Now Perimeter of two semi circles = 2πr = 2×(22/7)×3.5 = 22 m
And Perimeter of garden = 22+13+13
= 48 m. Answer
Answer - 4 : -
Area of the floor = 1080 m2 =1080 × 10000 cm2 =10800000 cm2 [∵ 1 m2 =10000 cm2]Area of 1 tile = 1 × base × height = 1 × 24 × 10 = 240 cm2Number of tiles required= 45000 tiles
Answer - 5 : -