The Total solution for NCERT class 6-12
Answer - 1 : -
Let f (x) = x2 –2
Answer - 2 : -
Answer - 3 : -
Find the derivativeof the following functions from first principle
(i) x3 –27
(ii) (x – 1) (x – 2)
(iii) 1 / x2
(iv) x + 1 / x – 1
Answer - 4 : -
(i) Let f (x) = x3 –27
From first principle
(ii) Let f (x) = (x – 1) (x – 2)
(iii) Let f (x) = 1 / x2
From first principle, we get
(iv) Let f (x) = x + 1 / x – 1
Answer - 5 : -
Answer - 6 : -
For some constantsa and b, find the derivative of(i) (x − a) (x − b)
(ii) (ax2 +b)2
(iii) x – a / x – b
Answer - 7 : -
(i) (x – a) (x – b)
(ii) (ax2 + b)2
= 4ax (ax2 + b)
Answer - 8 : -
Find the derivativeof
(i) 2x – 3 / 4
(ii) (5x3 +3x – 1) (x – 1)
(iii) x-3 (5+ 3x)
(iv) x5 (3– 6x-9)
(v) x-4 (3– 4x-5)
(vi) (2 / x + 1) – x2 / 3x – 1
Answer - 9 : -
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Answer - 10 : -