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Triangles EX 6.6 Solutions

Question - 1 : -

In Figure, PS is thebisector of QPR of ∆ PQR. Provethat QS/PQ = SR/PR

Answer - 1 : -


Solution

Question - 2 : - In Fig. 6.57, D is a point on hypotenuse AC of∆ABC, such that BD AC,DM BC and DN AB.

Answer - 2 : -

 Prove that: (i) DM_2 = DN . MC (ii) DN_2 = DM . AN.
Solution
Solution

Question - 3 : -

In Figure, ABC is atriangle in which ABC > 90° and AD CB produced. Prove that

AC2= AB2+BC2+ 2 BC.BD.

Answer - 3 : -

Question - 4 : -

In Figure, ABC is atriangle in which ABC < 90° and AD BC. 

Answer - 4 : -

Prove that

AC_2= AB_2+ BC_2 – 2 BC.BD.

Question - 5 : -

In Figure, AD is amedian of a triangle ABC and AM BC.

Answer - 5 : -

 Prove that :

(i) AC_2 = AD_2 + BC.DM + 2 (BC/2)_ 2

(ii) AB_2 = AD_2 – BC.DM + 2 (BC/2)_ 2

(iii) AC_2 + AB_2 = 2 AD_2 + ½ BC_2

Solution

Solution

Solution


Question - 6 : -

Prove that the sumof the squares of the diagonals of parallelogram is equal to the sum of thesquares of its sides.

Answer - 6 : -

Question - 7 : -

In Figure, twochords AB and CD intersect each other at the point P. Prove that :


Answer - 7 : -

(i) ∆APC ~ ∆ DPB

(ii) AP . PB = CP . DP

Solution


Question - 8 : -

In Fig. 6.62, twochords AB and CD of a circle intersect each other at the point P (whenproduced) outside the circle. 

Answer - 8 : -

Prove that:

(i) ∆ PAC ~ ∆ PDB

(ii) PA . PB = PC . PD.


Question - 9 : -

In Figure, D is apoint on side BC of ∆ ABC such that BD/CD = AB/AC. Prove that AD is thebisector of BAC.

Answer - 9 : -

Question - 10 : -

Nazima is flyfishing in a stream. The tip of her fishing rod is 1.8 m above the surface ofthe water 

Answer - 10 : - and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string (from the tip of her rod to the fly) is taut, how much string does she have out (see Figure)? If she pulls in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds?


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