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Chapter 4 Determinants Ex 4.2 Solutions

Question - 1 : -

Using the property ofdeterminants and without expanding, prove that:

Answer - 1 : -

Solution

Question - 2 : -

Using the property ofdeterminants and without expanding, prove that-

Answer - 2 : -


Solution

Here, the two rows R1 and R3 are identical.

Δ = 0.

Question - 3 : -

Using the property ofdeterminants and without expanding, prove that:

Answer - 3 : -


Question - 4 : -

Using the property ofdeterminants and without expanding, prove that:

Answer - 4 : -


By applying C→ C3 + C2, wehave:

Here, two columns C1 and Care proportional.

Δ = 0.

Question - 5 : -

Using the property ofdeterminants and without expanding, prove that:

Answer - 5 : -


Applying R2 → R2 − R3, we have:

Applying R1 ↔R3 and R2 ↔R3, we have:

Applying R→ R1 − R3, we have:

Applying R1 ↔R2 and R2 ↔R3, we have:

From (1), (2), and (3),we have:

Hence, the given resultis proved.

Question - 6 : -

By using properties ofdeterminants, show that:

Answer - 6 : -

We have,

Here, the two rows R1 and Rare identical.

Δ = 0.

Question - 7 : -

By using properties ofdeterminants, show that:

Answer - 7 : -


Applying R→ R2 + R1 and R→ R3 + R1, we have:

Question - 8 : -

By using properties ofdeterminants, show that:

Answer - 8 : -


(i)   (ii) 


Solution

(i) 

Applying R1 → R1 − RandR2 → R2 − R3, we have:

Applying R1 → R1 + R2, we have:

Expanding along C1, we have:

Hence, the given resultis proved.


(ii) Let

Applying C1 → C1 − CandC2 → C2 − C3, we have:

Expanding along C1, we have:

Hence, the given resultis proved.


Question - 9 : -

By using properties ofdeterminants, show that:

Answer - 9 : -


Applying R2 → R2 − RandR3 → R3 − R1, we have:

Applying R3 → R3 + R2, we have:

Expanding along R3, we have:

Hence, the given resultis proved.

Question - 10 : -

By using properties ofdeterminants, show that:

Answer - 10 : -

(i) 

(ii) 

Solution

(i) 

Applying R1 → R1 + R+ R3, we have:

Applying C2 → C2 − C1, C3 → C3 − C1, we have:

Expanding along C3, we have:

Hence, the given resultis proved.


(ii) 

Applying R1 → R1 + R+ R3, we have:

Applying C2 → C2 − CandC3 → C3 − C1, we have:

Expanding along C3, we have:

Hence, the given resultis proved.

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