The Total solution for NCERT class 6-12
Answer - 1 : -
(i) 32 × 34 × 38 =32+4+8 = 314 [am ÷ an =am+n](ii) 615 ÷ 610 = 615-10 =65 [am ÷an = am-n](iii) a3 × a2 = a3+2 =a5 [am ×an = am+n](iv) 7x × 72 = 7x+2 [am × an =am+n](v) (52)3 ÷53 = 52×3 ÷53 = 56 ÷53 = 56-3 =53 [(a3)n = amn,am ÷ an =am-n](vi) 25 × 55 = (2 × 5)5 =105 [am ×bm = (ab)m](vii) a4 × b4 = (ab)4 [am × bm =(ab)4](ix) (220 ÷ 215) × 23 =220-15 × 23=25 × 23 =25+3 = 28(x) 8t ÷ 82 =8t-2 [am ÷an = am-n]
Answer - 2 : -
Answer - 3 : -
(i) 10 × 1011 = 101+11 = 1012RHS = 10011 = (102)11 =10221012 ≠ 1022∴Statement is false.
(ii) 23 > 52LHS = 23 = 8RHS = 522 = 258 < 25∴ 23 < 52Thus, the statement is false.
(iii) 23 × 32 = 65LHS = 233 × 32 =8 × 9 = 72RHS = 65 = 6 × 6 × 6 × 6 × 6 =7776∴ 72 ≠7776∴ Thestatement is false.
(iv) 30 = (1000)0⇒ 1 = 1True [∵ a0 = 1]
Answer - 4 : - (i) 108 × 192 = 2 × 2 × 3 × 3 × 3 × 2 × 2 × 2 × 2 × 2× 2 × 2 × 3=28 × 34
Answer - 5 : -