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Coordinate Geometry Ex 7.3 Solutions

Question - 1 : -

Find the area of thetriangle whose vertices are:

Answer - 1 : -

(i) (2, 3), (-1, 0), (2, -4)

(ii) (-5, -1), (3, -5), (5, 2)

Solution

Solution

Question - 2 : -

In each of thefollowing find the value of ‘k’, for which the points are collinear.

Answer - 2 : -

(i) (7, -2), (5, 1), (3, -k)

(ii) (8, 1), (k, -4), (2, -5)

Solution

Question - 3 : -

Find the area of thetriangle formed by joining the mid-points of the sides of the triangle whosevertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to thearea of the given triangle.

Answer - 3 : -

Question - 4 : -

Find the area of thequadrilateral whose vertices, taken in order, are

(-4, -2), (-3, -5),(3, -2) and (2, 3).

Answer - 4 : -

Question - 5 : - You have studied in Class IX that a median ofa triangle divides it into two triangles of equal areas. Verify this result forΔABC whose vertices are A (4, – 6), B (3, – 2) and C (5, 2).

Answer - 5 : -

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