MENU

RD Chapter 9 Trigonometric Ratios of Multiple and Submultiple Angles Ex 9.1 Solutions

Question - 1 : - Prove the following identities:
√[(1 – cos 2x) / (1 + cos 2x)] = tan x

Answer - 1 : -

Let us consider LHS:

√[(1 – cos 2x) / (1 +cos 2x)]

We know that cos 2x = 1– 2 sin2 x

= 2 cos2 x – 1

So,

√[(1 – cos 2x) / (1 +cos 2x)] = √[(1 – (1 – 2sin2 x))/ (1 + (2cos2x – 1))]

= √[(1 – 1 + 2sin2 x) / (1 + 2cos2 x – 1)]

= √[2 sin2 x / 2 cos2 x]

= sin x/cos x

= tan x

= RHS

Hence proved.

Question - 2 : - sin 2x / (1 – cos 2x) = cot x

Answer - 2 : -

Let us consider LHS:

sin 2x / (1 – cos 2x)

We know that cos 2x = 1– 2 sin2 x

Sin 2x = 2 sin x cos x

So,

sin 2x / (1 – cos 2x) =(2 sin x cos x) / (1 – (1 – 2sin2 x))

= (2 sin x cos x) / (1 –1 + 2sin2 x)]

= [2 sin x cos x / 2 sin2 x]

= cos x/sin x

= cot x

= RHS

Hence proved.

Question - 3 : - sin 2x / (1 + cos 2x) = tan x

Answer - 3 : -

Let us consider LHS:

sin 2x / (1 + cos 2x)

We know that cos 2x = 1– 2 sin2 x

= 2 cos2 x – 1

Sin 2x = 2 sin x cos x

So,

sin 2x / (1 + cos 2x) =[2 sin x cos x / (1 + (2cos2x – 1))]

= [2 sin x cos x / (1 +2cos2 x – 1)]

= [2 sin x cos x / 2 cos2 x]

= sin x/cos x

= tan x

= RHS

Hence proved.

Question - 4 : -

Answer - 4 : -


Question - 5 : - [1 – cos 2x + sin 2x] / [1 + cos 2x + sin 2x] = tan x

Answer - 5 : -

Let us consider LHS:

[1 – cos 2x+ sin 2x] / [1 + cos 2x + sin 2x]

We know that, cos 2x = 1 – 2 sin2 x

= 2 cos2 x – 1

Sin 2x = 2 sin x cos x

So,

Question - 6 : - [sin x + sin 2x] / [1 + cos x + cos 2x] = tan x

Answer - 6 : -

Let us consider LHS:

[sin x + sin2x] / [1 + cos x + cos 2x]

We know that, cos 2x = cos2 x– sin2 x

Sin 2x = 2 sin x cos x

So,

= RHS

Hence proved.

Question - 7 : - cos 2x / (1 + sin 2x) = tan (π/4 – x)

Answer - 7 : -

Let us consider LHS:

cos 2x / (1 + sin 2x)

We know that, cos 2x = cos2 x – sin2 x

Sin 2x = 2 sin x cos x

So,

Question - 8 : - cos x / (1 – sin x) = tan (π/4 + x/2)

Answer - 8 : -

Let us consider LHS:

cos x / (1 – sin x)

We know that, cos 2x = cos2 x – sin2 x

Cos x = cos2 x/2 – sin2 x/2

Sin 2x = 2 sin x cos x

Sin x = 2 sin x/2 cos x/2

So,

Question - 9 : -

Answer - 9 : -


Question - 10 : -

Answer - 10 : -


Free - Previous Years Question Papers
Any questions? Ask us!
×