The Total solution for NCERT class 6-12
Answer - 51 : -
Hence proved.
Answer - 52 : -
Answer - 53 : -
Answer - 54 : - All integers which are even, between 101 and 999 are = 102, 104, 106, 108, … 998
Answer - 55 : -
= 250 x 251 + 505 x 50– 25 x 510= 62750 + 25250 – 12750= 88000 – 12750= 75250
Answer - 56 : - In an A.P. a is the first term, d, the common difference a is the nthterm and Sn is the sum of first n terms,
Answer - 57 : -
Answer - 58 : -
Answer - 59 : -
Answer - 60 : -
Given : Resham saved₹450 in the first month and raised her saving by ₹20 every month and saved innext 12 months.First term (a) = 450Common difference (d) = 20and No. of terms (n) = 12We know sum of n terms is in A.P.Sn = (n/2) [2a + (n – 1) d]Sn = (12/2) [2x 450 + (12 – 1) x 20]=> Sn = 6[900 + 240]=> Sn = 6720Here we can see that Resham saved ₹ 6720 which is more than ₹ 6500.So, yes Resham shall be able to send her daughter to school.