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Question -

Two objects of masses 100 g and 200 g are moving along the same line anddirection with velocities of 2 ms–1 and 1 ms–1,respectively. They collide and after the collision, the first object moves at avelocity of 1.67 ms–1. Determine the velocity of the second object.



Answer -

Assuming that thefirst object is object A and the second one is object B, it is given that:

Mass of A (m1)= 100g

Mass of B (m2)= 200g

Initial velocity of A(u1) = 2 m/s

Initial velocity of B(u2) = 1 m/s

Final velocity of A (v1)= 1.67 m/s

Final velocity of B (v2)=?

Total initial momentum= Initial momentum of A + initial momentum of B

= m1u1 +m2u2

= (100g) × (2m/s) +(200g) × (1m/s) = 400 g.m.sec-1

As per the law ofconservation of momentum, the total momentum before collision must be equal tothe total momentum post collision.

v2 =1.165 m/s

Therefore, thevelocity of object B after the collision is 1.165 meters per second.

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