Question -
Answer -
Given, the Bullet’smass (m1) = 50 g
The rifle’s mass (m2)= 4kg = 4000g
Initial velocity ofthe fired bullet (v1) = 35 m/s
Let the recoilvelocity be v2.
Since the rifle wasinitially at rest, the initial momentum of the rifle = 0
Total momentum of therifle and bullet after firing = m1v1 + m2v2
As per the law ofconservation of momentum, the total momentum of the rifle and the bullet afterfiring = 0 (same as initial momentum)
Therefore, m1v1 +m2v2 = 0
Therefore, the recoilvelocity of the rifle is 0.4375 meters per second in the direction opposite tothe trajectory of the bullet (backward direction).