Question -
Answer -
(a) Given, forceexerted by the train (F) = 40,000 N
Force of friction =-5000 N (the negative sign indicates that the force is applied in the oppositedirection)
Therefore, the netaccelerating force = sum of all forces = 40,000 N + (-5000 N) = 35,000 N
(b) Total mass of thetrain = mass of engine + mass of each wagon = 8000kg + 5 × 2000kg
The total mass of thetrain is 18000 kg.
As per the second lawof motion, F = ma (or: a = F/m)
Therefore,acceleration of the train = (net accelerating force) / (total mass of thetrain)
= 35,000/18,000 = 1.94ms-2
The acceleration of thetrain is 1.94 m.s-2.