Question -
Answer -
Let the two stones meet after a time t.
(i) For the stone dropped from the tower:
Initial velocity, u = 0
Let the displacement of the stone in time t from the top of the tower be s.
Acceleration due to gravity, g = 9.8 m sтИТ2
From the equation of motion,
(ii)┬аFor the stone thrown upwards:
Initial velocity,┬аu┬а= 25 msтИТ1
Let the displacement of the stone from theground in time┬аt┬аbe┬аsтАШ.
Acceleration due to gravity, g = тИТ9.8 m sтИТ2
Equationof motion,
Thecombined displacement of both the stones at the meeting point is equal to theheight of the tower 100 m.
In4 s, the falling stone has covered a distance given by equation (1) as
Therefore,the stones will meet after 4 s at a height (100 тИТ 80) = 20 m from the ground