The Total solution for NCERT class 6-12
A bullet of mass 10 g travelling horizontally with a velocity of 150 m s–1 strikesa stationary wooden block and comes to rest in 0.03 s. Calculate the distanceof penetration of the bullet into the block. Also calculate the magnitude ofthe force exerted by the wooden block on the bullet.
Given, mass of thebullet (m) = 10g (or 0.01 kg)
Initial velocity ofthe bullet (u) = 150 m/s
Terminal velocity ofthe bullet (v) = 0 m/s
Time period (t) = 0.03s
To find the distanceof penetration, the acceleration of the bullet must be calculated.
Therefore, forceexerted by the wooden block on the bullet (F) = 0.01kg × (-5000 ms-2)
= -50 N
This implies that thewooden block exerts a force of magnitude 50 N on the bullet in the directionthat is opposite to the trajectory of the bullet.