MENU
Question -

(a) Show that the normal component of electrostaticfield has a discontinuity from one side of a charged surface to another givenby  

Where is a unit vector normal tothe surface at a point and σ is the surface charge density at that point. (Thedirection of is from side 1 to side 2.)Hence show that just outside a conductor, the electric field is σ 

(b) Show that the tangential component of electrostaticfield is continuous from one side of a charged surface to another. [Hint: For(a), use Gauss’s law. For, (b) use the fact that work done by electrostaticfield on a closed loop is zero.]



Answer -

(a) Electric field on one side of a charged body is E1 andelectric field on the other side of the same body is E2.If infinite plane charged body has a uniform thickness, then electric field dueto one surface of the charged body is given by,

Where,

 = Unit vector normal to the surface at a point

σ = Surface charge density at that point

Electric field due to the other surface of the chargedbody,

Electric field at any point due to the two surfaces,

Since inside a closedconductor,  = 0,

Therefore, the electricfield just outside the conductor is 

(b) When a charged particle is moved from one point to theother on a closed loop, the work done by the electrostatic field is zero.Hence, the tangential component of electrostatic field is continuous from oneside of a charged surface to the other.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×