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Question -

(a) Figure 9.35 shows across-section of a ‘light pipe’ made of a glass fibre of refractive index 1.68.The outer covering of the pipe is made of a material of refractive index 1.44.What is the range of the angles of the incident rays with the axis of the pipefor which total reflections inside the pipe take place, as shown in the figure.

(b) What is the answerif there is no outer covering of the pipe?



Answer -

(a) Refractiveindex of the glass fibre, 

Refractive index of the outer covering of thepipe,  = 1.44

Angle of incidence = i

Angle of refraction = r

Angle of incidence at the interface = i

The refractive index (μ) of the innercore − outer core interface is given as:

For the critical angle, total internalreflection (TIR) takes place only when, i.e., i > 59°

Maximumangle of reflection,

Let,

be the maximum angle ofincidence.

Therefractive index at the air − glass interface,

We have the relation forthe maximum angles of incidence and reflection as:

Thus, all the rays incident at angles lyingin the range 0 < i < 60° will suffer total internalreflection.

(b) If the outer covering ofthe pipe is not present, then:

Refractiveindex of the outer pipe,

For the angle of incidence i =90°, we can write Snell’s law at the air − pipe interface as:

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