The Total solution for NCERT class 6-12
(a) At what distanceshould the lens be held from the figure in
Exercise 9.29 in order toview the squares distinctly with the maximum possible magnifying power?
(b) What is themagnification in this case?
(c) Is the magnificationequal to the magnifying power in this case?
(a) The maximum possiblemagnification is obtained when the image is formed at the near point (d =25 cm).
Image distance, v = −d =−25 cm
Focal length, f = 10 cm
Object distance = u
According to the lensformula, we have:
Hence, to view the squaresdistinctly, the lens should be kept 7.14 cm away from them.
(b) Magnification =
(c) Magnifyingpower =
Sincethe image is formed at the near point (25 cm), the magnifying power is equal tothe magnitude of magnification.