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Question -

(a) A giant refractingtelescope at an observatory has an objective lens of focal length 15 m. If aneyepiece of focal length 1.0 cm is used, what is the angular magnification ofthe telescope?

(b) If this telescope isused to view the moon, what is the diameter of the image of the moon formed bythe objective lens? The diameter of the moon is 3.48 × 106 m, and the radius oflunar orbit is 3.8 × 108 m.



Answer -

Focal length of the objective lens, fo = 15 m = 15 × 102 cm

Focal length of the eyepiece, fe = 1.0 cm

(a) The angularmagnification of a telescope is given as:

Hence, the angularmagnification of the given refracting telescope is 1500.

(b) Diameter of the moon, d =3.48 × 106 m

Radius of the lunar orbit, r0 = 3.8 × 108 m

Let be the diameter of theimage of the moon formed by the objective lens.

The angle subtended by thediameter of the moon is equal to the angle subtended by the image.

Hence,the diameter of the moon’s image formed by the objective lens is 13.74 cm

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