Question -
Answer -
Area of the virtual image of eachsquare, A = 6.25 mm2
Area of each square, A0 = 1 mm2
Hence, the linearmagnification of the object can be calculated as:
Focal length of the magnifying glass, f =10 cm
According to the lensformula, we have the relation:
Thevirtual image is formed at a distance of 15 cm, which is less than the nearpoint (i.e., 25 cm) of a normal eye. Hence, it cannot be seen by the eyesdistinctly.