Question -
Answer -
(a) For a concave mirror, thefocal length (f) is negative.
∴f < 0
When the object is placed on the left sideof the mirror, the object distance (u) is negative.
∴u < 0
For image distance v, we canwrite the lens formula as:
The object lies between f and2f.
Using equation (1), weget:
∴
is negative, i.e., v isnegative.
Therefore, the image lies beyond 2f.
(b) For a convex mirror, thefocal length (f) is positive.
∴ f > 0
When the object is placed on the left sideof the mirror, the object distance (u) is negative.
∴ u < 0
For image distance v, we havethe mirror formula:
Thus, the image is formedon the back side of the mirror.
Hence, a convex mirroralways produces a virtual image, regardless of the object distance.
(c) For a convex mirror, thefocal length (f) is positive.
∴f > 0
When the object is placed on the left sideof the mirror, the object distance (u) is negative,
∴u < 0
Forimage distance v, we have the mirror formula:
Hence, the image formed is diminished and islocated between the focus (f) and the pole.
(d) For a concave mirror, thefocal length (f) is negative.
∴f < 0
When the object is placed on the left sideof the mirror, the object distance (u) is negative.
∴u < 0
It is placed between the focus (f)and the pole.
For image distance v, we havethe mirror formula:
The image is formed on theright side of the mirror. Hence, it is a virtual image.
For u <0 and v > 0, we can write:
Magnification, m 
> 1
Hence,the formed image is enlarged.