Question -
Answer -
Take a┬а
┬аemission nuclear reaction:
┬аWe know that:
Mass of┬а
m1┬а= 223.01850 uMass of┬а
m2┬а= 208.98107 uMass of,┬аm3┬а= 14.00324 uHence, the┬аQ-value of thereaction is given as:
Q┬а= (m1┬атИТ┬аm2┬атИТ┬аm3)┬аc2
= (223.01850 тИТ 208.98107 тИТ 14.00324)┬аc2
= (0.03419┬аc2) u
But 1 u = 931.5 MeV/c2
тИ┤Q┬а= 0.03419 ├Ч931.5
= 31.848 MeV
Hence, the┬аQ-value of the nuclearreaction is 31.848 MeV. Since the value is positive, the reaction isenergetically allowed.
Now take a┬а
emission nuclear reaction:
We know that:
Mass of┬аm1┬а= 223.01850
m2┬а= 219.00948Mass of,┬аm3┬а= 4.00260Q-value of this nuclear reaction isgiven as:
Q┬а= (m1┬атИТ┬аm2┬атИТ┬аm3)┬аc2
= (223.01850 тИТ 219.00948 тИТ 4.00260) C2
= (0.00642┬аc2) u
= 0.00642 ├Ч 931.5 = 5.98 MeV
Hence, the┬аQ┬аvalue of thesecond nuclear reaction is 5.98 MeV. Since the value is positive, the reactionis energetically allowed.