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Question -

Two moving coil meters, M1 andM2 have the following particulars:

R1 =10 Ω, N1 = 30, A1 =3.6 × 10–3 m2, B1 = 0.25T

R2 =14 Ω, N2 = 42, A2 =1.8 × 10–3 m2, B2 = 0.50T

(The spring constants areidentical for the two meters).

Determine the ratio of (a)current sensitivity and (b) voltage sensitivity of M2 and M1.



Answer -

For moving coil meter M1:

Resistance, R1 =10 Ω

Number of turns, N1 =30

Area of cross-section, A1 =3.6 × 10–3 m2

Magnetic field strength, B1 =0.25 T

Spring constant K1 = K

For moving coil meter M2:

Resistance, R2 =14 Ω

Number of turns, N2 =42

Area of cross-section, A2 =1.8 × 10–3 m2

Magnetic field strength, B2 =0.50 T

Spring constant, K2 = K

(a) Current sensitivityof M1 is given as:

And, current sensitivity of M2 isgiven as:

 Ratio 

Hence, the ratio of currentsensitivity of M2 to M1 is 1.4.

(b) Voltagesensitivity for M2 is given as:

And, voltage sensitivity for M1 isgiven as:

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