Question -
Answer -
The situation isrepresented in the following figure.
A and B are two parallelplates close to each other. Outer region of plate A is labelled as I, outer region of plate B is labelledas III, and the regionbetween the plates, A and B, is labelled as II.
Chargedensity of plate A,σ = 17.0 × 10−22 C/m2
Charge density of plate B, σ = −17.0 × 10−22 C/m2
In the regions, I and III, electric field E is zero. This is because charge isnot enclosed by the respective plates.
Electric field E in region II is given by the relation,
Where,
∈0 = Permittivity offree space = 8.854 × 10−12 N−1C2 m−2
∴
= 1.92 × 10−10 N/C
Therefore, electric fieldbetween the plates is 1.92 × 10−10 N/C.