The Total solution for NCERT class 6-12
Three capacitors each of capacitance 9 pF are connectedin series.
(a) What is the total capacitance of the combination?
(b) What is the potential difference across eachcapacitor if the combination is connected to a 120 V supply?
(a) Capacitance of each of the three capacitors, C =9 pF
Equivalent capacitance (C’)of the combination of the capacitors is given by the relation,
1C’=1C+1C+1C⇒1C’=19+19+19=13⇒C’=3 pFTherefore,total capacitance of the combination is
3 pF.
(b) Supply voltage, V = 120 V
Therefore, the potential difference acrosseach capacitor is 40 V.