The Total solution for NCERT class 6-12
Thephotoelectric cut-off voltage in a certain experiment is 1.5 V. What is themaximum kinetic energy of photoelectrons emitted?
Photoelectric cut-off voltage, V0 =1.5 V
Where,
e = Charge on an electron = 1.6 × 10−19 C
Therefore,the maximum kinetic energy of the photoelectrons emitted in the givenexperiment is 2.4 × 10−19 J.