(a)The maximum kinetic energyis given by the photoelectric effect as:
Where,
h = Planck’s constant = 6.626 × 10−34 Js
Hence, the maximum kineticenergy of the emitted electrons is 0.345 eV.
(b)For stopping potential
, we can write the equation forkinetic energy as:
Hence, the stoppingpotential of the material is 0.345 V.
(c)Maximum speed of theemitted photoelectrons = v
Hence,the relation for kinetic energy can be written as:
Where,
m = Mass of an electron = 9.1 × 10−31 kg
Hence,the maximum speed of the emitted photoelectrons is 332.3 km/s.