Question -
Answer -
The radius of the innermost orbitof a hydrogen atom, r1 = 5.3 × 10−11 m.
Let r2 be the radius of the orbit at n = 2. It is related to the radius ofthe innermost orbit as:
For n =3, we can write the corresponding electron radius as:
Hence, the radii of an electronfor n = 2 and n = 3 orbits are 2.12 × 10−10 m and 4.77 × 10−10 m respectively.