The Total solution for NCERT class 6-12
Suppose the initial charge on thecapacitor in Exercise 7.7 is 6 mC. What is the total energy stored in thecircuit initially? What is the total energy at later time?
Capacitance of thecapacitor, C = 30 μF = 30×10−6 F
Inductance of the inductor, L =27 mH = 27 × 10−3 H
Charge on the capacitor, Q =6 mC = 6 × 10−3 C
Total energy at a later time willremain the same because energy is shared between the capacitor and theinductor.