The Total solution for NCERT class 6-12
Suppose that the particlein Exercise in 1.33 is an electron projected with velocity vx=2.0 × 106 m s−1. If E between theplates separated by 0.5 cm is 9.1 × 102 N/C, where will theelectron strike the upper plate? (| e | =1.6 × 10−19 C, me =9.1 × 10−31 kg.)
Velocity of the particle, vx =2.0 × 106 m/s
Separation of the twoplates, d = 0.5 cm = 0.005 m
Electric field between thetwo plates, E = 9.1 × 102 N/C
Charge on anelectron, q = 1.6 × 10−19 C
Mass of an electron, me =9.1 × 10−31 kg
Let the electron strikethe upper plate at the end of plate L, when deflection is s.
Therefore, the electronwill strike the upper plate after travelling 1.6 cm.