MENU
Question -

Keeping the source frequencyequal to the resonating frequency of the series LCR circuit,if the three elements, Land arearranged in parallel, show that the total current in the parallel LCR circuitis minimum at this frequency. Obtain the current rms value in each branch ofthe circuit for the elements and source specified in Exercise 7.11 for thisfrequency.



Answer -

An inductor (L), acapacitor (C), and a resistor (R) is connected in parallel witheach other in a circuit where,

L =5.0 H

C =80 μF = 80 × 10−6 F

R =40 Ω

Potential of the voltagesource, V = 230 V

Impedance (Z) of the givenparallel LCR circuit is given as:

Where,

ω = Angular frequency

Atresonance,

Hence, the magnitude of isthe maximum at 50 rad/s. As a result, the total current is minimum.

Rms current flowing throughinductor L is given as:

Rms current flowing throughcapacitor C is given as:

Rms current flowing throughresistor R is given as:

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×