Question -
Answer -
Frequency of the electromagneticwave, ν = 2.0 × 1010 Hz
Electricfield amplitude, E0 = 48 V m−1
Speed oflight, c = 3 × 108 m/s
(a) Wavelength of a wave is given as:
(b) Magneticfield strength is given as:
(c) Energydensity of the electric field is given as:
And, energy density of themagnetic field is given as:
Where,
∈0 = Permittivity of free space
μ0 = Permeability offree space
We havethe relation connecting E and B as:
E = cB … (1)
Where,
… (2)
Puttingequation (2) in equation (1), we get
Squaring both sides, we get
