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Question -

In a p-n junction diode, the current I can be expressed as

where I0 iscalled the reverse saturation current, is the voltage across thediode and is positive for forward bias and negative for reverse bias, and isthe current through the diode, kBis theBoltzmann constant (8.6×10−5 eV/K) and T is the absolute temperature. Iffor a given diode I0 = 5 × 10−12 Aand T = 300 K, then

(a) What will be the forward current at a forward voltage of0.6 V?

(b) What will be the increase in the current if the voltageacross the diode is increased to 0.7 V?

(c) What is the dynamic resistance?

(d) What will be the current if reverse bias voltage changesfrom 1 V to 2 V?



Answer -

In a p-n junction diode, the expression for current isgiven as:

Where,

I0 =Reverse saturation current = 5 × 10−12 A

T = Absolutetemperature = 300 K

kB =Boltzmann constant = 8.6 × 10−5 eV/K = 1.376 × 10−23 JK−1

V = Voltageacross the diode

(a) Forward voltage, V = 0.6 V

Current, I 

.

Therefore, the forward current is about 0.0256 A.

(b) For forward voltage, V =0.7 V, we can write:

Hence, the increase in current, ΔI − I

= 1.257 −0.0256 = 1.23 A

(c) Dynamic resistance 

(d) If the reverse bias voltage changes from 1 V to 2 V,then the current (I)will almost remain equal to I0 in both cases. Therefore, the dynamicresistance in the reverse bias will be infinite.

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