Question -
Answer -
Let┬аI1┬аand┬аI2┬аbe the intensity of the two light waves. Theirresultant intensities can be obtained as:

Where,
= Phase difference between thetwo waves
Formonochromatic light waves,


Phase difference =┬а
Since path difference = ╬╗,
Phasedifference,┬а

Given,
IтАЩ =┬аK

When path difference
Phase difference,┬а
Hence, resultant intensity,┬а

Using equation (1), we can write:

Hence, the intensity of light at a point where thepath difference is┬а
is┬а
units.