Question -
Answer -
The magnetic field onthe axis of the magnet at a distance d1 = 14 cm,can be written as:
Where,
M = Magnetic moment
= Permeability of freespace
H = Horizontal component of the magneticfield at d1
If the bar magnet isturned through 180°, then the neutral point will lie on the equatorial line.
Hence, the magneticfield at a distance d2, on the equatorial line of themagnet can be written as:
Equating equations(1) and (2), we get:
The new null points willbe located 11.1 cm on the normal bisector.