Question -
Answer -
The given fusion reaction is:
Amount of deuterium, m =2 kg
1 mole, i.e., 2 g of deuteriumcontains 6.023 × 1023 atoms.
∴2.0 kg of deuteriumcontains 
It can be inferred from the givenreaction that when two atoms of deuterium fuse, 3.27 MeV energy is released.
∴Totalenergy per nucleus released in the fusion reaction:
Power of the electric lamp, P =100 W = 100 J/s
Hence, the energy consumed by thelamp per second = 100 J
The total time for which theelectric lamp will glow is calculated as:
