Question -
Answer -
(a)┬аElectricfield intensity,┬а
┬а= 3 ├Ч 103┬а├оN/C
Magnitudeof electric field intensity,┬а
= 3 ├Ч 103┬аN/C
Side of the square,┬аs┬а=10 cm = 0.1 m
Area of the square,┬аA┬а=s2┬а= 0.01 m2
The plane of the square isparallel to the┬аy-z┬аplane. Hence, angle between the unitvector normal to the plane and electric field,┬а╬╕┬а= 0┬░
Flux (╬ж) through the planeis given by the relation,
╬ж=┬а
= 3 ├Ч 103┬а├Ч 0.01├Ч cos0┬░
= 30 N m2/C
(b)┬аPlanemakes an angle of 60┬░ with the┬аx-axis. Hence,┬а╬╕┬а=60┬░
Flux,┬а╬ж┬а== 3 ├Ч 103┬а├Ч 0.01├Ч cos60┬░
┬а= 15 N m2/C