The Total solution for NCERT class 6-12
Calculate the height of thepotential barrier for a head on collision of two deuterons. (Hint: The heightof the potential barrier is given by the Coulomb repulsion between the twodeuterons when they just touch each other. Assume that they can be taken ashard spheres of radius 2.0 fm.)
When two deuterons collidehead-on, the distance between their centres, d is given as:
Radius of 1st deuteron+ Radius of 2nd deuteron
Radius of a deuteron nucleus = 2fm = 2 × 10−15 m
∴d =2 × 10−15 + 2 × 10−15 =4 × 10−15 m
Charge on a deuteron nucleus =Charge on an electron = e = 1.6 × 10−19 C
Where,
= Permittivity of freespace
Hence, the height of thepotential barrier of the two-deuteron system is 360 keV.