MENU
Question -

Acompound microscope consists of an objective lens of focal length 2.0 cm and aneyepiece of focal length 6.25 cm separated by a distance of 15 cm. How far fromthe objective should an object be placed in order to obtain the final image at(a) the least distance of distinct vision (25 cm), and (b) at infinity? What isthe magnifying power of the microscope in each case?



Answer -

Focal length of the objective lens, f1 = 2.0 cm

Focal length of the eyepiece, f2 = 6.25 cm

Distance between the objective lens and theeyepiece, d = 15 cm

(a) Least distance of distinct vision, 

Image distance for theeyepiece, v2 = −25 cm

Object distance for the eyepiece = u2

According to the lensformula, we have the relation:

Image distance for the objective lens,

Object distance for the objective lens= u1

According to the lensformula, we have the relation:

Magnitude of the object distance,  = 2.5 cm

The magnifying power of acompound microscope is given by the relation:

Hence, the magnifyingpower of the microscope is 20.

(b) The final image is formedat infinity.

Imagedistance for the eyepiece,

Object distance for the eyepiece = u2

According to the lensformula, we have the relation:

Image distance for the objective lens,

Object distance for the objective lens= u1

According to the lensformula, we have the relation:

Magnitude of the object distance,  = 2.59 cm

The magnifying power of acompound microscope is given by the relation:

Hence,the magnifying power of the microscope is 13.51.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×