Question -
Answer -
Both the charges can be locatedin a coordinate frame of reference as shown in the given figure.
At A, amount of charge, qA =2.5 × 10−7C
At B, amount of charge, qB =−2.5 × 10−7 C
Total charge of the system,
q = qA + qB
= 2.5 × 10−7 C −2.5 × 10−7 C
= 0
Distance between two charges atpoints A and B,
d =15 + 15 = 30 cm = 0.3 m
Electric dipole moment of thesystem is given by,
p = qA × d= qB × d
= 2.5 × 10−7 ×0.3
= 7.5 × 10−8 C malong positive z-axis
Therefore, the electric dipolemoment of the system is 7.5 × 10−8 C m along positive z−axis.