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Question -

A short bar magnetplaced in a horizontal plane has its axis aligned along the magneticnorth-south direction. Null points are found on the axis of the magnet at 14 cmfrom the centre of the magnet. The earth’s magnetic field at the place is 0.36G and the angle of dip is zero. What is the total magnetic field on the normalbisector of the magnet at the same distance as the null−point (i.e., 14 cm)from the centre of the magnet? (At null points, field due to amagnet is equal and opposite to the horizontal component of earth’s magneticfield.)



Answer -

Earth’s magnetic fieldat the given place, H = 0.36 G

The magnetic field at adistance d, on the axis of the magnet is given as:

Where,

= Permeability of freespace

M = Magnetic moment

The magnetic field atthe same distance d, on the equatorial line of the magnet is givenas:

Total magnetic field,

Hence, the magneticfield is 0.54 G in the direction of earth’s magnetic field.

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