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Question -

A prismis made of glass of unknown refractive index. A parallel beam of light isincident on a face of the prism. The angle of minimum deviation is measured tobe 40°. What is the refractive index of the material of the prism? Therefracting angle of the prism is 60°. If the prism is placed in water(refractive index 1.33), predict the new angle of minimum deviation of aparallel beam of light.



Answer -

Angle of minimum deviation,  = 40°

Angle of the prism, = 60°

Refractive index of water, µ =1.33

Refractiveindex of the material of the prism = 
The angle of deviation is related to refractiveindexas:

Hence, the refractiveindex of the material of the prism is 1.532.

Sincethe prism is placed in water, let be the new angle ofminimum deviation for the same prism.

The refractive index ofglass with respect to water is given by the relation:

Hence,the new minimum angle of deviation is 10.32°.


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