Question -
Answer -
(a) Electric flux, Φ = −1.0 × 103 Nm2/C
Radius of the Gaussiansurface,
r = 10.0 cm
Electric flux piercing outthrough a surface depends on the net charge enclosed inside a body. It does notdepend on the size of the body. If the radius of the Gaussian surface isdoubled, then the flux passing through the surface remains the same i.e., −103 N m2/C.
(b) Electric flux is given bythe relation,
Where,
q = Net charge enclosed by the spherical surface
∈0 = Permittivity offree space = 8.854 × 10−12 N−1C2 m−2
∴
= −1.0 × 103 × 8.854 × 10−12
= −8.854 × 10−9 C
= −8.854 nC
Therefore, the value ofthe point charge is −8.854 nC.