The Total solution for NCERT class 6-12
A parallel plate capacitor with air betweenthe plates has a capacitance of 8 pF (1pF = 10тИТ12┬аF). What willbe the capacitance if the distance between the plates is reduced by half, andthe space between them is filled with a substance of dielectric constant 6?
Capacitance between the parallel plates of the capacitor,C = 8 pF
Initially, distance between the parallelplates was┬аd┬аand it was filled with air. Dielectric constantof air,┬аk┬а= 1
Capacitance,┬аC, is given by theformula,
Where,
A┬а=Area of each plate
= Permittivity of free space
Taking ratios of equations (i) and (ii), we obtain
Therefore, the capacitance between theplates is 96 pF.