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Question -

A coil of inductance 0.50 H andresistance 100 ╬й is connected to a 240 V, 50 Hz ac supply.

(a)┬аWhat isthe maximum current in the coil?

(b)┬аWhat is the time lagbetween the voltage maximum and the current maximum?



Answer -

Inductance of the inductor,┬аL┬а=0.50 H

Resistance of the resistor,┬аR┬а=100 ╬й

Potential of the supplyvoltage,┬аV┬а= 240 V

Frequency of the supply,┬а╬╜┬а=50 Hz

(a)┬аPeakvoltage is given as:

Angular frequency of the supply,

╧Й = 2 ╧А╬╜

= 2╧А ├Ч 50 = 100 ╧А rad/s

Maximum current in the circuit isgiven as:

(b)┬аEquationfor voltage is given as:

V┬а=┬аV0┬аcos┬а╧Йt

Equation for current is given as:

I┬а=┬аI0┬аcos(╧Йt┬атИТ┬а╬ж)

Where,

╬ж = Phase difference betweenvoltage and current

At time,┬аt┬а= 0.

V┬а=┬аV0(voltageis maximum)

For╧Йt┬атИТ┬а╬ж┬а=0 i.e., at time

I┬а=┬аI0┬а(currentis maximum)

Hence,the time lag between maximum voltage and maximum current is

Now, phase angle┬а╬жisgiven by the relation,

Hence, the time lag betweenmaximum voltage and maximum current is 3.2 ms.

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