The Total solution for NCERT class 6-12
A 100 μF capacitor in series witha 40 Ω resistance is connected to a 110 V, 60 Hz supply.
(a) What isthe maximum current in the circuit?
(b) What isthe time lag between the current maximum and the voltage maximum?
Capacitance of thecapacitor, C = 100 μF = 100 × 10−6 F
Resistance of the resistor, R =40 Ω
Supply voltage, V =110 V
(a) Frequencyof oscillations, ν= 60 Hz
Angular frequency,
Maximum current is given as:
(b) In acapacitor circuit, the voltage lags behind the current by a phase angle ofΦ.This angle is given by the relation:
Hence, the time lag betweenmaximum current and maximum voltage is 1.55 ms.