Question -
Answer -
It is given that T1 = 298 K
∴T2 =(298 + 10) K
= 308 K
We alsoknow that the rate of the reaction doubles when temperature is increased by10°.
Therefore,let us take the value of k1 = k and that of k2 = 2k
Also, R = 8.314 J K−1 mol−1
Now,substituting these values in the equation:
We get:
= 52897.78 J mol−1
=52.9 kJ mol−1