Question -
Answer -
The reaction X → Y follows secondorder kinetics.
Therefore,the rate equation for this reaction will be:
Rate = k[X]2 (1)
Let [X] = a mol L−1,then equation (1) can be written as:
Rate1 = k .(a)2
= ka2
If theconcentration of X is increased to three times, then [X] = 3a mol L−1
Now, therate equation will be:
Rate = k (3a)2
= 9(ka2)
Hence,the rate of formation will increase by 9 times.