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Question -

The cell in which the followingreactions occurs:



Answer -

has = 0.236 V at 298 K.

Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.

Answer

Here, n =2, T = 298 K

We know that:

= −2 × 96487 × 0.236

= −45541.864 J mol−1

= −45.54 kJ mol−1

Again,
−2.303RT log Kc

= 7.981

Kc =Antilog (7.981)

= 9.57 × 107



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