Question -
Answer -
2HI(g) → H2 + I2(g)
is 209.5 kJ mol−1 at 581K. Calculate the fraction ofmolecules of reactants having energy equal to or greater than activation energy?
Answer
the given case:
Ea = 209.5 kJ mol−1 = 209500 J mol−1
T = 581 K
R = 8.314 JK−1 mol−1
Now, the fraction of molecules of reactantshaving energy equal to or greater than activation energy is given as:
