The Total solution for NCERT class 6-12
Silver crystallises infcc lattice. If edge length of the cell is 4.07 × 10−8 cm and density is 10.5 g cm−3, calculate the atomic mass of silver.
It is given that theedge length, a = 4.077 × 10−8 cm
Density, d =10.5 g cm−3
As the lattice isfcc type, the number of atoms per unit cell, z = 4
We also know that, NA = 6.022 × 1023 mol−1
Using the relation:
= 107.13 gmol−1
Therefore, atomic massof silver = 107.13 u